Question

A particle of mass m = 1 kg is tied to a string and a
horizontal force F = 20 N is applied on the particle as
shown in figure. The tension in the string is (g = 10
m/s)
20 N
5130 N
5VON
520 N
3120 N​

Answer 1

Answer:

mass= 1kg

force=20

gravitational acceleration=10m/s

tension=?

solution:

F=T-W

T=F+mg

T= 20+1(10)

T= 20+10

T= 30 N *Answer*

*I think it sould be helpful for you*

Answer 2

Answer:

5 root 20

Explanation:

Write down the components of T and then equate the forces

mg= T sin theta ---> (1)

20 N = T cos theta  ----> (2)

On dividing , (1) and (2) we get,

tan theta = 1/2

USE PYTHAGORUS THEOREM,

adjacent side = 2 units

opposite side = 1 unit

therefore, hypotenuse = root 5 units ----> (3)

so now , we can find T using (3),

                            T* 1/ ROOT 5 = 1* 10

                                             T= 10 ROOT 5

                                              T= 5*2* ROOT 5

                                               T= 5 * ROOT (5*4)

                                                T= 5 * ROOT 20

hope it helps!!!