A particle of mass M and carrying charge Q is launched with initial speed v and at an angle of 0 relative to the horizontal direction. When it reaches the maximum height it enters a region of uniform magnetic field. In the region it moves at constant velocity in the horizontal direction.
Determine the direction and strength of the magnetic field
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Explanation:
The force F on a charge q moving with velocity v in a magnetic field B is given by ,
F=qvBsinθ ,
where θ= angle between v and B ,
in the given diagram the angle between v and B is , θ=180
o
,
therefore F=qvBsin180=0 ,
charge q doesn't experience any force so it will follow a straight line out of the page .
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