Question

A particle of mass m and carrying charge -q, is moving around a charge +q, along a circular path of radius r. Find period of revolution of the charge​

Answer 1

Answer:

a

Explanation:

centripetal force = mvv/r

electrostatic force= kq1q2/rr

mvv/r= kq1q2/rr

vv= kq1q2/mr

v= $\sq\sqrt\\kq1q2/mr$

time period= 2πr/v

                  = 2πr$\sqrt{mr}$/$\sqrt{kq1q2}$

                  = ${} \sqrt{4\pi ^{2}r^{2}mr }$/$\sqrt{ q1q2/4\pi }$∈

                  = $\sqrt{16\pi ^{3}r^{3}m }$∈/$\sqrt{q1q2}$ in negative ( means attract krenge ek dusre ko )