Question

a particle of mass m and charge -q circulates around a fixed charge q in a circle of radius r under electrostatic force the total energy of system is

Answer 1

If the charge particle is moving in an circular path, then the electrostatic force will balances the necessary centrifugal force.

Therefore, In Equilibrium,

  Centrifugal force = Electrostatic force

   mv²/r = kQ₁Q₂/r²

  1/2 mv² = kQ₁Q₂/r

   $\Big[K.E. = kQ_1Q_2/r \Big]$

Potential energy of the charge = -KQ₁Q₂/r

Total energy of the system = Kinetic energy + Potential energy

 = 0

Hence, total energy of the system is 0.

Hope it helps.

Answer 2

Answer:-kqq/2r

Explanation:centrifugal force=electrostatic force

i. e., mv^2/r=kq^2 /r^2

So, 1/2mv^2 =kq^2 /2r=K.E

P.E=-kq^2 /r

T. E=PE+KE=(kqq/2r) +(-kqq/r) =

-kqq/2r