Question

A particle of mass M and charge q is projected into a region having a perpendicular uniform magnetic field B of width d. Find the angle of deviation of particle as it comes out of the magnetic field .

Answer 1

Let, the angle of deviation=θ and the redius of the path= r
We are given,width of the magnetic field=d.
We know, r=(mv/qB)
Again we know, sinθ=d/r
For d=r we can write,
d=(mv/qB)=r
=> sinθ =(mv/qB)/(mv/qB)
=> sinθ=1
=> sinθ=sin90°
=> θ=90°
Hence, we can say that the angle of deviation will be 90°