Physics, asked by annmarybmarachery, 6 days ago

a particle of mass m and charge q is released from rest in uniform electric field E. the momentum attained by the particle after moving a distance x is (a) (2mqEx)^1/2 (b) (mqE^2x)1/2 (c) (mqEx)1/2 (d) 2mqEx

Answers

Answered by khushbuluderekar

2

Answer:

Correct option is CqEy

K.E acquired = work done

= force× distance =qE×y=qEy

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