A particle of mass m and charge q is released from the origin in a region occupied by electric field E and magnetic field B. B = - Boî, Ē= E, î. The speed of particle as a function of x- coordinate is
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Explanation:
B
=B
0
j
^
E
=E
0
k
^
The particle have initial velocity zero, So electric field will be responsible for to move in opposite direction of electric field.
Magnetic force on the particle does not increase the speed of the particle since
F
mag
.
v
=0 (∠90
∘
)
F
electric
=qE
k
^
⇒
a
=
m
qE
k
^
Since acceleration is constant applying the one-dimensional kinematics equation:
v
2
−u
2
=2a
z
∴v
2
=
m
2qEz
since initial speed u=0
⇒v=
m
2qEz
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Answer:
ndndhaghaakkansnsbsbbdjdjdj
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