A particle of mass m and radius of gyration K is rotating with an angular acceleration
.The Torque acting on the particle is
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Answered by
39
Torque=moment of inertia * alpha
=I*α
=MR² * α
for particle mass R=K
=MK² * α
=I*α
=MR² * α
for particle mass R=K
=MK² * α
Answered by
7
T=Ia
T = torque
I= moment of inertia
=>I=mxk^2 (k= rad. of gyration)
final T=mx(k^2)
xa
T = torque
I= moment of inertia
=>I=mxk^2 (k= rad. of gyration)
final T=mx(k^2)
xa
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