Question

A particle of mass M at rest decays into two particles of mass M1 and M2 having non zero velocities calculate the ratio of de Broglie wavelength of This particle .

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Answer 1

Answer:

From law of conservation of momentum,

P1=P2P1=P2 (in opposite directions)

Now de-Broglie wavelength is given by

  λ=hp,  λ=hp, where h = Planck's constant

Since magnitude of momentum (p) of both the particles is

equal, therefore λ1=λ2λ1=λ2

or λ1/λ2=1

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Answer 2

ⒽⓁⓄ ⓜⓐⓣⓔ

de Broglie wavelength = h/mv

according to law of conservation of momentum

0=m1v1+m2v2

|m1v1|=|m2v2|

now,lemda 1/lemda2= |m2v2|/|m1v1|

= 1

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