A particle of mass m collides with a stationary particle and continues to move at an angle of 45° with respect to the original direction. The second particle also recoils at an angle of 45° to this direction. The mass of the second particle is (collision is elastic)
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Answer:
Apply principle of conservation of momentum along x-direction,
mu=mv
1
cos45+Mv
2
cos45
mu=
2
1
(mv
1
+Mv
2
) ...(1)
along y−direction,
o=mv
1
sin45−Mv
2
sin45
o=(mv
1
−Mv
2
)
2
1
...(2)
Coefficient of e=1=
ucos45
v
2
−v
1
cos90
Restution
⇒
2
u
v
2
=1
⇒u=
2
v
2
...(3)
solving eqn (1), (2), & (3) we get
M=m
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