Question

A particle of mass m describe a circle of radius r the centre retail acceleration of the particle is four by our square the momentum of the particle

Answer 1

Centrepetal Accl. of rotating particle is v^2/r

So v^2/r= 4/r^2

V= 2/✓r

Momentum will be linear equal to

MV =2m/✓r

There is no angular momentum as the particle is not rotating about its own axis of mass.