Physics, asked by MiniDoraemon, 7 months ago

A particle of mass m excutes simple harmonic motion with amplitude a and frequency v . The average kinetic energy during its motion from the position of equiblirium to the end is [AIEEE 2007] ​

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Answered by nehaimadabathuni123
1

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Answered by TheLifeRacer
6

Explanation:- As we know that average kinetic energy of particle = 1/4ma²ω²

  • = 1/4ma²ω²
  • = 1/4ma² (2πv)²
  • = π²v²ma²

∴ The average kinetic energy during its motion from the position of equiblirium to the end is π²v²ma²

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