Question

A particle of mass m having a charge q enters into a circular region of radius r with velocity v directed towards the centre. The strength of magnetic field is

b. Find the angle deviation in the path of the article.

Answer 1

We have the given data as mass= m , charge = q, radius = r, velocity = v, and magnetic field strength = b. Let ∅ be the angle deviation.

Now centrifugal force = mv²/r

Force exerted due to magnetic field = bqv sin∅

Since both this force are equal, Hence equating the above two eqn we get,

mv²/r = bqv sin∅

=> sin∅ = mv/bqr

=> ∅ = sin^-1(mv/bqr)

Which is the required angle of deviation.

Answer 2

Answer:

This is correct sir

Explanation:

That is answer of deviation