A particle of mass M having charge Q is projected in a uniform magnetic field B as shown in figure. Net deviation of the path of the particle due to magnetic field is equal to
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Answer:
Explanation:
The radius of the circular orbit
is r= mv/qB
The deviation θ may be obtained
from in as
sin Θ =d/r= dBq/mv
Θ= sin^-1(dBq/mv)
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