Question

A particle of mass `m` is describing a circular path of radius `r` with uniform speed. If l is the angular momentum of the particle about the axis of the circle then, the kinetic energy of the particle is:

Answer 1

l = iw
K. E. =
$\frac{m {v}^{2} }{2}$
=1/2 i w^2r^2
= 1/2 i (w^2/r^2)

Answer 2

Answer:

L^2/2mvr

Explanation:

L = mvr

mv = L/r

kE = P^2/2m

= (L/r)^2/2m

= L^2/2mr^2