Question

A particle, of mass m, is executing a simple harmonic motion of amplitude a and angular frequency Omega. Write expression for its potential energy and kinetic energy when it is displaced through a distance x from its mean position.

Answer 1

Explanation:

KE = 1/2 k A²

as ke is max at mean due to max velocity

PE = 1/2 k x²

pe may 0 at mean

Answer 2

Explanation:

kE =1/2kAsq

as ke is max at mean due to max velocity.

pE=1/2 kx sq

pe may 0 at mean