Question

A particle of mass m is executing uniform circular motion on a path of radius r. If p is the magnitude of its linear momentum. The radial fore acting on the particle is

Answer 1

Answer:

Radial force =(p^2)/mr

Explanation:

Let V be the linear velocity of body

p=m V

so V =p/m

the radial force = m(V^2)/r

= (p^2)/mr

Answer 2

Answer:

F=(p^(2))/(m r)

Explanation:

`F = (mv^(2))/(r ) = (m)/(r ) ((p)/(m))^(2) = (p^(2))/(m r)