Question

A particle of mass m is moving at speed v perpendicular to an uniform rod of length d and mass m = 6m which pivots around a frictionless axle running through its centre. It strikes and sticks to the end of the rod. The moment of inertia of the rod about its centre is then the angular speed of the system just after the collision is :

Answer 1

Answer:

By conservation of angular momentum about pivot.

L=Iω

2

mvd

=[

12

Md

2

+m(

2

d

)

2

]ω

=(

2

md

2

+

4

md

2

)ω

=

4

3

md

2

ω⇒

3

2

d

v

=ω

Explanation:

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