A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ‘a’ is varying with time t as ac = k2 rt2, where k is a constant. the power delivered to the particle by the forces acting on it is
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Hello!!
a(c) = dv/dt = k² rt²
∫dv = ∫ k² rt² .dt
v = k²r t³ / 3
W = F . v
F = mv²/r
W = mv²/r . v
W = m(v)³/r
W = m/r( k²r t³ / 3 )³
a(c) = dv/dt = k² rt²
∫dv = ∫ k² rt² .dt
v = k²r t³ / 3
W = F . v
F = mv²/r
W = mv²/r . v
W = m(v)³/r
W = m/r( k²r t³ / 3 )³
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2
Answer:
Power varies linearly with time. Check the attachment.
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