Question

a particle of mass 'm' is moving on a circular path of radius 'r' with uniform speed 'v' . rate of change of linear momentum is

(1) Zero
(2) independent of speed
(3) proportional to radius 'r'
(4) proportional to v²

kindly explain the answer​

Answer 1

Answer:

It may be independent of speed

Explanation:

The formula for finding momentum is P=mv

where P= momentum, m= mass and v= the velocity

Momentum is directly proportional to mass and velocity. It simply means if mass increases/ decreases by a factor, momentum will also increase with the same factor. Same relationship with mass. If a larger mass is used, the momentum will be large too. If a smaller mass is used, the momentum will be small too.

Answer 2

Answer:

4

Explanation:

By Newton 's second law rate of change of linear momentum calls force . So this question is only asking about force on particle in uniform circular motion .

Now only force working on particle in this condition is centripetal force which is keeping particle in to orbit .

Now Force is a vector quantity . it's direction is changing over time so it's not constant .

Although it's magnitude is constant . Which is

$f = \frac{m {v}^{2} }{r} = m \omega {}^{2} r$

Is it independent of speed no it is proportional to square of it .

Is it proportional to r no because v is given constant not omega (angular velocity ) So it is inversely proportional.