Question

A particle of mass m is moving with a constant velocity parallel to the y axis. If at t=0 the particle is at point A(2m,0) then the angular momentum with respect to the origin on the passing time?​

Answer 1

Answer:

remain constant as L= mvrsin theta

(perpendicular distance )

Answer 2

Angular Momentum (L) will be constant.

Angular momentum (L) = mxv

where, m is mass of the moving particle

x is the distance of the particle on x axis from the origin

v is velocity of the particle

It is given that the particle is moving parallel to you axis. Therefore it's distance on the x axis from origin will remain constant.

So we can say that Angular momentum of the particle about the origin will remain constant.