A particle of mass m is moving with constant velocity v parallel to the x axis as shown in the figure. It's angular momentum about origin is
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A body of mass M is moving with a constant velocity v parallel to the x-axis. Let the perpendicular distance between the X-axis and the path of the particle be r. Then the angular momentum of the body about X-axis is given,
L = r × p, where r is the perpendicular distance between the path of the particle and X-axis, and p is the linear momentum of the particle. Since r and p are perpendicular to each other we have ,
| L | = M | v | |r|= M v r
Since M, v, and r are all constant L is constant.
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✔HOPE THIS HELPS YOU ✔
A body of mass M is moving with a constant velocity v parallel to the x-axis. Let the perpendicular distance between the X-axis and the path of the particle be r. Then the angular momentum of the body about X-axis is given,
L = r × p, where r is the perpendicular distance between the path of the particle and X-axis, and p is the linear momentum of the particle. Since r and p are perpendicular to each other we have ,
| L | = M | v | |r|= M v r
Since M, v, and r are all constant L is constant.
×××××××××××××××××××××××××××××××
✔HOPE THIS HELPS YOU ✔
Anonymous:
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6
Given:
Particle of mass = m
Velocity = v
Velocity is parallel to = x-axis
To find:
Angular momentum about origin
Solution:
The position vector is specified as -
= ai + bj
Angular momentum = m ( ai + b) x vi
Calculating the cross product -
The angular momentum of the particle will be - mvb
This also represents in the direction of z-axis
Thus, in the scalar form
= mvb
Answer: Angular momentum about origin is mvb.
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