A particle of mass m is moving with horizontal speed 6m/sec as shown in figure. If m<<M then for one dimensional elastic collision, the speed of lighter particle after collision will be (in SI unit)
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Answered by
1
Step-by-step explanation:
speed of lighter particle = V1 m/s
after collision
V1=
u
(m1–m2)(m1+m2)
1+
(m1+m2)
(2m2u2)
here m1=m,m2=M
given m<<M
hence
m1=0
V1=–u1+
M
(2M)
u2
V1=–u1+2u2
V1=–5+(2)(3)
V1=1m/s
lighter particle will move in original direction with speed 1m/s
Answered by
1
Mass - weight
Hope it helps Thank you
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