Question

A particle of mass m is moving with velocity v ⃗₁, it is given
an impulse such that the velocity becomes v ⃗₂. Then
magnitude of impulse is equal to
(a) m(v ⃗₂ - v ⃗₁)
(b) m(v ⃗₁ - v ⃗₂) (c) m x (v ⃗₂ - v ⃗₁)
(d) 0.5m(v ⃗₂ - v ⃗₁)

Answer 1

Explanation:

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Answer 2

Answer:

your answer is in the attachment

Explanation:

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