A particle of mass m is moving yz- plane with
a uniform velocity v with its trajectory running
parallel to +ve y-axis and intersecting z-axis
at z=a. The change in its angular momentum
about the origin as it bounces elastically from
a wall at y = constant is
1) mva i
2) 2 mva i
3)-mva i
4) -2amv i
Answers
Answered by
1
Answer:
mvaeˆx
2mvaeˆx
ymveˆx
2ymveˆx
Answer :
B
Solution :
The initial velocity is vi=veˆy and after reflection from the wall, the final velocity is vf=−veˆy. The trajectory is described as position vector r×yeˆy+aeˆz
Hence, the change in angular momentum is
τ×m(vf−vi)=2mvaeˆx
Explanation:
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