A particle of mass m is placed at each vertices of equilateral triangle. If the particle of 5 kg is placed at the centroid of triangle, then find the gravitational force on it. The distance between centroid to vertice is 2 m.
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Answer:
g = GMm/d²
= 6.67×10^(-11) × 5 × m/2²
= 33.35×10^(-11)×m/4
= 8.3375 × 10^(-11)m
= 0.000000000083375m N/kg
= vertices = 3
total force = 3×8.3375×10^(-11)m
= 25.0125 × 10^(-11)m
= 2.5×10^(-10)×m N/kg
hope it helped (:
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