Physics, asked by samyakbharilya107, 10 months ago

A particle of mass m is placed over a horizontal circular table rotating with an angular velocity omega about a vertical axis passing through its centre. The distance of the object from the axis is r. Find the force of friction f between the particle and the table.

Answers

Answered by qwfun
0

The frictional force F between the particle and table is mω² or fN.

  • Frictional force is f times the normal force (i.e. fN), where f is the coefficient of friction
  • If the particle is not moving with respect to the table so there must be a force in the radial direction which must be equal to mv²/r or mω², if fN>mv²/r then the frictional force will be equal to mv²/r

If in case mv²/r > fN then friction force will be fN as this is the upper limit for the frictional force.

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