A particle of mass m is projected with a velocity v making an angle 45 with horizontal.Find magnitude of angular momentum
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a particle of mass m is projected with a velocity v making an angle of 45 degrees with the horizontal. the magnitude of the angular momentum of the projectile about the point pf projection when the particle is at its max height
8 years ago
Answers : (2)
Dear Pranay
max height ,H= v2sin2θ/2g
velocity at max height = ux= vcosθ
angular momentum= muxH
and putting θ =450
angular momentum = mv3/g4√2
All the best.
AKASH GOYAL
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