Math, asked by bharatdkhadse7711, 1 year ago

A particle of mass m is projected with a velocity v making an angle 45 with the horizontal. the magnitude of angular momentum

Answers

Answered by likithasanjana
6
at a height h, 
h =v^2sin^2a/2g       (where a is the angle made by the horizontal)
   x component of velocity at that point = ucosa
angular momentum is r *p        (where r is h, p is mucosa)
                                  =v^2sin^2a/2g m ucosa
                                    =v^3m/4 g \sqrt2
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