Question

A particle of mass M is projected with velocity V making an angle of 45 degree with the horizontal when the particle and on the ground level the magnitude of change in momentum will be

Answer 1

Answer:

There will be no change in the magnitude of momentum.

Explanation:

As when the object reaches the ground it attains the same velocity but in opposite direction. So, both the momentums will have same magnitude but different directions.

Answer 2

Answer:

$\sqrt{2}$ mv

Explanation:

Here the particle follows a projectile motion.

In projectile Motion the velocity along the x-axis does not change.

∴ Change in momentum along x-axis is zero.

we will only consider the velocity along the y-axis to get the change in momentum of the particle.

so,

velocity along the y-axis = vsin45°

|ΔP|= m(Δv)

|ΔP|= m[vsin45°-(-vsin45°)]

|ΔP|=2×mv×sin45°

|ΔP|=2×mv×1/$\sqrt{2}$

|ΔP|= $\sqrt{2}$mv