Physics, asked by sonipariii, 1 year ago

A particle of mass m is projected with velocity v
making an angle of 45° with the horizontal. When
the particle lands on the level around the
magnitude of the change in its momentum will be
(AIPMT (Prelims)-2008)
(1) Zero
(2) 2 mv
Zoo
SU
em
(4) m2​

Answers

Answered by Pranjal01
1

Answer:

mv sqrt(2)

.....

hmmmm

Answered by akshaygandhirock
7

ΔΡ=2mv sinθ2mv*1/√2=√2mv

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