A particle of mass m is projected with velocity v
making an angle of 45° with the horizontal. When
the particle lands on the level around the
magnitude of the change in its momentum will be
(AIPMT (Prelims)-2008)
(1) Zero
(2) 2 mv
Zoo
SU
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(4) m2
Answers
Answered by
1
Answer:
mv sqrt(2)
.....
hmmmm
Answered by
7
ΔΡ=2mv sinθ2mv*1/√2=√2mv
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