Question

A particle of mass m is suspended
by the two strings a and b each of
length' as shown. Based on this
simple information, answer the
following questions.
In equilibrium,tension in the string a is ​

Answer 1

Answer:

Hence the tension is $\frac{2mg}{\sqrt{3}}$

Explanation:

• Let Tension in string a be T_{a} and that in string b be T_{b}.
• Now the weight of the ball of mass m  suspended by the two strings a and b is mg
• On resolving the components of tension on string a for condition of equillibrium we get
  $T_{a} Cos 60^0 = T_{b}\\T_{a}Sin 60^0 = mg$
• Now on solving the above equation we get that tesion in string a is
  $T_{a} = \frac{mg}{Sin 60}\\T_{a} = \frac{mg}{\frac{\sqrt{3} }{2}}\\T_{a} = \frac{mg *2}{\sqrt{3} }$
• Hence the tension is $\frac{2mg}{\sqrt{3}}$
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