Question

A particle of mass m is taken from point A to B very slowly by force F parallel
to x-axis along smooth circular track of radius R in vertical plane. If m = 2 kg, g
= 10 m/s2 and R = 1.5 m then the work done by force F, in joules, is equal
to_
​

Answer 1

Answer:

Work done by force = 30 Joules

Explanation:

Given :       mass m = 2kg;     acceleration a = 10$m/s^2$;    Radius R = 1.5m;

We know he force on a body is given by the formula:

F=m.a

Force F = m.a = 2.10 = 20N

Work done is given by the formula:

W=F.S

where,

F denotes force acting on the body,

S is the displacement made by the body in the direction of force.

Displacement of the body in the direction of force = radius of the curve

= R

Hence, the Work done by the force in displacing the body from A to B =

W = F.R

Hence, Work done = F.R = 20*(1.5) = 30J

#SPJ3

Answer 2

A particle of mass m is taken from point A to B very slowly by force F parallel to x-axis along smooth circular track of radius R in vertical plane. If m = 2 kg, g= 10 m/s2 and R = 1.5 m then the work done by force F, in joules, is equal to

What is work -

Work done on an object is defined as the magnitude of the force multiplied by the distance moved by the object in the direction of the applied force.

                        Work done = force × distance. = F × s.

Explanation:

Given :      mass m = 2kg      

                 acceleration a = 10  

                  Radius R = 1.5m

The formula for force

                      Force F =m.a

                 Force F = m.a = 2.10 = 20N

Work done is given by the formula:

                              W=F.S

where,

          F denotes force ,

         S is the displacement .

Displacement of the body in the direction of force = radius of the curve= R

the Work done by the body from A to B

                                W = F.R

Hence,

                Work done = F.R = 20*(1.5) = 30J

Work done by force = 30 Joules

#SPJ2