Question

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A particle of mass m is thrown horizontally from the top of a tower and another particle of mass 2m is thrown
vertically upward. The acceleration of centre of is​

Answer 1

The acceleration of centre of mass is g

Explanation:

Acceleration of both particles remains same (downwards) = acceleration due to gravity.

Mass and Acceleration of both particle is given below:

$m_1=m\;and \;m_2=2m$

$a_1 = a_2 = g$

Acceleration of centre of mass,$a_{cm}= \frac{m_1a_1+m_2a_2}{m_1+m_2}$

$=\frac{m(g)+2m(g)}{m+2m}$

$=\frac{3mg}{3m}$

$=g(downwards\;direction)$

Thus, acceleration of centre of mass is g