Physics, asked by kameswarihanumansett, 1 month ago

A particle of mass m is thrown vertically up with a speed u. The work done by
gravitational force as a particle reaches maximum height is

Answers

Answered by gsk515627

0

Answer:

g+F/mu2.

Explanation:

Loss in K.E. = Gain in P.E. + Work done against air drag i.e 21mu2=mgh+Fh=h(mg+F)

or h=2(g+F/m)u2

=2g+2F/mu2

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