A particle of mass m is thrown vertically up with a speed u. The work done by
gravitational force as a particle reaches maximum height is
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Answer:
g+F/mu2.
Explanation:
Loss in K.E. = Gain in P.E. + Work done against air drag i.e 21mu2=mgh+Fh=h(mg+F)
or h=2(g+F/m)u2
=2g+2F/mu2
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