A particle of mass m, makes a head-
on elastic collision with another
particle of mass m, at rest. m,
rebounds straight back with 4/9 of its
m.
initial kinetic energy. Then
is
m.
m
1
1)
2)
3
5
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Answer:
ANSWER
Given : m1=m m2=2m u2=0 u1=u
Let the velocity of mass m after the collision be v1.
Using v1=m1+m2(m1−em2)u1+(1+e)m2u2
v1=m+2m(m−1×2m)u+(1+1)2m(0)=3u
Thus final kinetic energy of m1, E1′=21mv12=21m×9u2=181mu2
Initial kinetic energy of m1
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