Question

A particle of mass m moves along the X-axis such that its displacement x is given in terms of time by the equation:
x=a1 + a2t – a31? + agt
where a1,a2,a2
and are positive constants. What is the force acting on the particle at any time t?
04​

Answer 1

Answer:

Answer :

F=m(12at2−6bt+2c)

Solution :

Here, x=at4−bt3+2ct2−3d(t)

velocity, υ=dxdt=4at3−3bt2+2ct−3d

Acceleration, a=dυdt=12at2−6bt+2c

Force F=ma=m(12at2−6bt+2c) .