A particle of mass m moves in the XY plane with
a velocity v along the straight line AB. If the
angular momentum of the particle with respect
to origin Ois L, when it is at A and Lg when it is
at B, then
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Answer:
from the definition of angular momentum,
L=r×P
at A
L(A)=mvr sin(theta) = mvd
at B
L(B) = mvr sin(theta) = mvd {d=rain(theta)}
therefore...
L(A)=L(B)
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