Question

A particle of mass m moves with constant speed v on a circular path of radius r. Find magnitude
of average force on it in half revolution.
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Answer 1

Answer:

As the velocity is constant but the direction of velocity changes continusly.

And After half revolution direction of velocity will be opposite So,

Change in momentum= Final momentum-initial momentum

= mv-(-mv) =2mv

Average force = change in momentum/ time

Time= Distance/speed

Distance in half revolution= 2π.r/2 = π.r

So,time= π.r/v

Average force= 2mv/(π.r/v)

= 2mv2 /π.r