A particle of mass M moving with a velocity 2v collides with another particle of mass 3 M moving with a velocity V in the same direction if it is perfectly inelastic collision the loss of ke of the system is
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Answered by
3
Answer:
56%
Explanation:
hey mate here is the explanation :
as the collision is inelastic the masses will move together
Assuming the speed of block A and B becomes v
1
i
^
+v
2
j
^
Writing momentum equation in x direction
m(2v)+2m(0)=3mv
1
⇒v
1
=
3
2v
Writing momentum equation in Y direction
m(0)+2m(v)=3mv
2
⇒v
2
=
3
2v
The velocity of both blocks will be
3
2v
i
^
+
3
2v
j
^
The loss in kinetic energy
2
1
m(2v)
2
+
2
1
2m(v)
2
−
2
1
3m(
3
2
2v
)
2
3mv
2
−
3
4
mv
2
=
3
5
mv
2
percentage loss
3mv
2
3
5
mv
2
×100=56 %
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