Question

A particle of mass m, moving with a velocity u makes a head-on elastic collision with a particle of mass 2m initially at rest. Show that the particle of mass m loses (combined weight of the cars) , i.e., 8/9)th of its initial kinetic energy in the collision

Answer 1

Answer:

Explanation:

MAUA-MBUB=V(MA+MB)

INITIAL VELOCITYB IS 0  AT REST

 MAUA-0=V(MA+MB)

MA+MB=MAUA/V

M=MA+MB

M=MAUA/V