Question

a particle of mass m moving with speed v towards east strike another particle of same mass moving with same speed towards north .after striking 2 particles fuse together .with what speed this new particle of mass 2 m will move in North East direction .

Answer 1

v/2 m/s speed . hope it helps

Answer 2

Answer:

V/√2

Explanation:

According to law of conservation of linear momentum along horizontal direction

mv + 0 = 2v'

v' = v/2

According to law of conservation of linear momentum long vertical direction

0 + mv = 2 mv'

v'y = v/2

Therefore Speed of the new mass 2m is

v'=√v'2x+v'2y

=v/√2