Physics, asked by kumarsrinivasa90, 11 months ago

A particle of mass 'm' moving with velocity 2v collides another particle of mass 3m moving with velocity
'V' in the same direction. If it is perfect inelastic collision, the loss of KE of the system is
27
a) mv2
mloo
a
)
b) 2 mv²
c) / mv²
d) zero
[a]
т
A bullet of mass – moving horizontally with velocity v strikes a block of mass 'm' and gets embedded
into it. The velocity of the block finally is
Ta
ην
V
V
b)
d) n(n+1)
n+1
n+1​

Answers

Answered by riya20074
2

Answer:

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