Question

A particle of mass m moving with velocity u makes an elastic one-dimensional collision with a stationary particle of mass m.They are in contact for a brief time T.Their force of interaction increases from 0 toF° linearly in time 1/2 T.Find the magnitude of F°?

Answer 1

Mass of the particle = m (Given)

Velocity of the particle = u (Given)

Time = T (Given)

Increase in force = 0 to F (Given)

Linear time = 1/2T (Given)

In an elastic collision of one dimension, velocities are interchanged between two equal masses. Therefore, all of the particle's angular momentum change would be mu. The impulse or region under the F-T graph will give the linear momentum shift.

Thus,

1/2 FT = u

or F = 2u/t

Thus, the magnitude of F will be 2u/t

Answer 2

Here is your answer user.