Question

A particle of mass m moving with velocity v northwards collides with another particle of mass m moving with velocity v eastwards.after the collision the two particles coalesce. what is the velocity of new particle.

Answer 1

Answer:

Explanation:

R = $\sqrt{A^{2} + B^{2} + 2ABcos}$θ

θ = 90

A = B = v

R = $\sqrt{v^{2} + v^{2} + 2v^{2}cos(90)}$

Cos(90) = 1

R = $\sqrt{4v^{2}}$

R = 2v

Velocity after collission = 2v