A particle of mass m performs vertical motion in a circle of radius r Its potential energy at the highest point is what
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a particle form of mass is less than circular radius so its change in potential energy
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it's potential energy at the highest point is maximum.if a particle of mass m revolves around a circular path of radius of r then at highest point it's potential energy..
U= massXgravitational accelerationXheight from the centre
= mgr......(1)
or at highest point final velocity v=0
so by using third eqn of motion...
v^2 = u^2 - 2 gr (h=r)
0 = u^2 - 2 gr
2gr = u^2
or r = u^2/2g
so by using of (1)
we get potential energy U = mg X u^2/2g
U = mu^2/2
U= massXgravitational accelerationXheight from the centre
= mgr......(1)
or at highest point final velocity v=0
so by using third eqn of motion...
v^2 = u^2 - 2 gr (h=r)
0 = u^2 - 2 gr
2gr = u^2
or r = u^2/2g
so by using of (1)
we get potential energy U = mg X u^2/2g
U = mu^2/2
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