a particle of mass m rests on a horizontal floor with which it has a coefficient of static friction m. it is desired to make the body move by applying the minimum possible force f.
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Answered by
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Hey buddy!!
we know that Frictional force always opposes the relative motion between the objects.
therefore, the static frictional force is given as
* Normal force
where, is coefficient of static force
therefore if a particle of mass "m" rests on the floor it's normal force would be mg
here the coefficient of static friction is given to be "m"
therefore frictional force is m*mg =m^2g
and the minimum force required to move the body would be equal to the frictional force and that is
m^2g
Hope this helps !! ^_^
we know that Frictional force always opposes the relative motion between the objects.
therefore, the static frictional force is given as
where,
therefore if a particle of mass "m" rests on the floor it's normal force would be mg
here the coefficient of static friction is given to be "m"
therefore frictional force is m*mg =m^2g
and the minimum force required to move the body would be equal to the frictional force and that is
m^2g
Hope this helps !! ^_^
Answered by
0
Answer:
Answer is F=mg cos theta, theta =tan^-1(u)
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