A particle of mass (m) revolving in horizontal circle of radius (R) with uniform speed v. When particle goes from one end to other end of diameter , then :-
A. K.E changes by 1/2mv^2
B. K.E change by mv^2
C. No change in momentum
D. Change in momentum is 2mv
Answers
Answered by
7
Ans:- option d is correct.
Because there is no change in kinetic energy for uniform circular motion. And at diametrically opposite point, direction of velocity will be opposite to each other.
P
-(mv)-(mv)= -2mv
Because there is no change in kinetic energy for uniform circular motion. And at diametrically opposite point, direction of velocity will be opposite to each other.
P
-(mv)-(mv)= -2mv
Answered by
1
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Explanation:
correct option is D
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