Question

A particle of mass m strikes another particle of same mass at rest elastically after collision if velocity of one of the particle is 3i-2j them the other must jave velocity equals to

Answer 1

Answer:

$-3i+2j$

Explanation:

Let mass of each particle =m

$m_1=m,m_2=m$

Let initial velocity one particle which is moving =$u_$=0

And initial velocity of another particle which is at rest=$u_2=0$

After collision

Momentum of these particles =$m_1v_1+m_2v_2$

Where $v_1$=Velocity of one particle

$v_2=$ Velocity of another particle

Bu conservation of linear momentum

Initial momentum=Final momentum after collision

$0=m_1v_1+m_2v_2$

Substitute the values then we get

$0=m(3i-2j)+mv_2$

$-3i+2i=v_2$

$v_2=-3i+2j$m/s

Hence, the velocity of other particle must have =$-3i+2j$m/s

Answer 2

Answer: 2i+3j

Explanation: assume collision to be oblique elastic collision where particle move perpendicular to each other after collision

v1.v2=0

v1= 3i-2j. v2= 2i+3j

Please see attachment