A particle of mass m strikes elasticallyon a wall with velocity v at an angle of 60 degree from the wallthen magnitudeof change in momentum of ball along the wall is
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The velocity of the particle after hitting the wall elastically is same in magnitude but opposite in direction as the mass of the wall will be very large when compared to mass of the particle.
Therefore the change in momentum will be m(v-(-v)) =2mv(two times of the initial Momentum).
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Therefore the change in momentum will be m(v-(-v)) =2mv(two times of the initial Momentum).
Hope it helps.
Pls mark it as the brainliest.
kohila:
wrong answer
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